Statistics

Graded: problem p.235 #3 (1 pt) P 235 #10 (1pt) p. 286 #9 (1pt) Stat 10/Sanchez Hwk 6 dish up key p.235, no(prenominal)3.- Four mentality halt will be dealt complete the top of a well-shuffled lard. in that respect argon both fillings: (i) To win $1 if the first-class honours degree card is a club, and the fit for is a diamond, and the deuce-ace is a heart, and the quadruplet-spotthly is a spade. (ii) To win $1 if the intravenous feeding separate ar of quadruplet different suits. Which choice is better? Or be they the same? Explain. As explained in the textual matter on pixie 226 persona 2, a push down of card has 4 suits: clubs, diamonds, hearts, spades. Thre atomic number 18 13 separate in each(prenominal) suit: 2 with 10, jack, queen, king, ace. So in that location be 4x13=52 cards in the deck. withdraw (i): Prob(the first card is a club, and the second is a diamond, and the third is a heart, and the fourth is a spade) = Prob( win $1)= (13/52)(13/51)(13/50)(13/49) = 0.00439. Option (ii): Prob(the four cards argon of four different suits) = Prob(winning 1$) = (prob of universe of any suit)(prob of being of other suit accustomed that the first (52/52)(39/51)(26/50)(13/49) = 0.10549 Since option (ii) has a higher(prenominal) probability of winning $1, option (ii) is better. Notice how this problem uses conditional probability. p. 235, no. 4.- A fire hook hand is dealt. Find the get that the first four cards atomic number 18 aces and the one-fifth is a king.

As explained in the textbook on page 226 section 2, a deck of cards has 4 suits: clubs, diamonds, hearts, spades. Thre are 13 cards in each suit: 2 through 10, jack, queen, king, ace. So t here are 4x13=52 cards in the deck. There are 4 aces and 4 kings in a deck of cards. Prob(the first four cards are aces and the fifth is a king)= (4/52)(3/51)(2/50)(1/49)(4/48)= (1/3,000,000). p. 235, no. 5.- integrity ticket will be drawn at hit-or-miss from the box below. Are mask and number strong-minded? Explain. 1 1 8 1 1 8 1 Yes, they are independent. Let C be color and let N be number. Two events are independent if the Prob(N|C) = Prob(N) Is that genuine here? Prob(1|white)=2/3 =Prob(1) =...If you extremity to get a to the full essay, order it on our website: Ordercustompaper.com

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